type FlipArguments<T extends Function> = T extends (...p: infer args) => infer R ? (...p: args) => R : never;
Solution by wendao-liu #35056
type Reverse<T extends unknown[]> = T extends [infer F, ...infer R] ? [...Reverse<R>, F] : [];
type FlipArguments<T extends (...args: any[]) => any> = T extends (...args: infer P) => infer U
? (...args: Reverse<P>) => U
: never;
Solution by devshinthant #34953
type Reverse<T extends any[]> = T extends [infer First, ...infer Rest] ? [...Reverse<Rest>, First] : []
type FlipArguments<T extends (...args: any[]) => any> = T extends (...args: infer Args) => infer U ? (...args:Reverse<Args>) => U : never
Solution by maximallain #34779
// your answers
type Reverse<T> = T extends [infer F, ...infer Rest] ?
[...Reverse<Rest>, F]
: T
type FlipArguments<T extends (...args: any) => any> = (...args: Reverse<Parameters<T>>) => ReturnType<T>
Solution by Jayce-liang #34768
type Reverse<A extends any[], U extends any[] = []> = A extends [...infer rest, infer R] ? Reverse<rest, [...U, R]> : U
type FlipArguments<T extends Function> = T extends (...args: infer P) => infer R ? (...args: Reverse<P>) => R : never
Solution by ouzexi #34058
by jiangshan (@jiangshanmeta) #medium #arguments
Implement the type version of lodash's _.flip.
Type FlipArguments<T> requires function type T and returns a new function type which has the same return type of T but reversed parameters.
For example:
type Flipped = FlipArguments<(arg0: string, arg1: number, arg2: boolean) => void>
// (arg0: boolean, arg1: number, arg2: string) => void
View on GitHub: https://tsch.js.org/3196
...
type Reverse<A extends unknown[]> = A extends [infer L, ...infer R]
? [...Reverse<R>, L]
: A
type FlipArguments<T extends (...args: any) => any> = T extends (...args: [...infer A]) => ReturnType<T>
? (...args: Reverse<A>) => ReturnType<T>
: T
Solution by veralex #33811
type Reversed<A> = A extends [infer F, ...infer Rest] ? [...Reversed<Rest>, F] : [];
type FlipArguments<T extends (...args: any[]) => any> = T extends (...args: infer A) => infer R
? (...args: Reversed<A>) => R
: never;
Solution by kai-phan #32517
type FlipArguments<T extends (...args: any[]) => any, U extends any[] = []> = T extends (
...args: infer Args
) => infer RT
? Args extends [...infer F, infer R]
? FlipArguments<(...args: F) => RT, [...U, R]>
: (...args: U) => RT
: T;
Solution by gasmg #32209
type Reverse<T extends unknown[]> = T extends [... infer R, infer L] ? [L, ...Reverse<R>] : T;
type FlipArguments<T extends Function> = T extends (...args: infer A) => infer R ? (...args: Reverse<A>) => R : never;
Solution by ricky-fn #31919
type Reverse<T extends unknown[]> = T extends [infer F, ...infer E] ? [...Reverse<E>, F]:[]
type FlipArguments<T extends (...args:any[]) => any> = T extends (...args:infer P) => infer U ? (...args: Reverse<P>)=>U : never
Solution by Zhen-code #31882
type Reverse<T extends any[], U extends any[] = []> = T extends [infer A, ...infer B] ? Reverse<B, [...U, A]> : U
type FlipArguments<T extends Function> = T extends (...arg: infer B) => infer C ? (...arg0: Reverse<B>) => C : never
Solution by dreamluo-plus #30620
// your answers
type ReversTypeArr<T extends unknown[]> =T extends [infer F, ...infer Rest] ? [...ReversTypeArr<Rest> , F] :
[]
type FlipArguments<T extends (...ags: any)=> any >= T extends (...args: infer R) => infer U ? (...args: ReversTypeArr<R>)=> U : never
Solution by kerolossamir165 #29523
Solution:
type ReverseArray<Arr extends any[]> = Arr extends [infer First, ...infer Last] ? [...ReverseArray<Last>, First] : Arr;
type FlipArguments<T extends (...args: any[]) => any> = T extends (...args: [...infer A]) => infer R
? (...args: ReverseArray<A>) => R : never;
Solution by DmitriiBr #29520
type Reverse<T extends any[]> = T extends [infer A, ...infer B] ? [...Reverse<B>, A]: [];
type R = Reverse<[1, 2, 3, 4]>;
type FlipArguments<T extends Function> = T extends (...args: infer E) => any ?
(...args: Reverse<E>) => any : never;
type Flipped = FlipArguments<(arg0: string, arg1: number, arg2: boolean) => void>;
const flipped: Flipped = (a: boolean, b: number, c: string) => {
};
Solution by sundial-dreams #29493
// your answers
type TransferToRe<T extends any[] ,Arr extends any[]=[]> =T["length"] extends 0? Arr: T extends [infer A,...infer B]? TransferToRe<B,[A,...Arr]>:Arr
type FlipArguments<T extends (...vaules:any[])=>any,Arr extends any[]=[]> =T extends (...vaules:infer A)=>infer C
? (...vaules:TransferToRe<A>)=>C:never
Solution by sunhk123456 #29190
type Reverse<T extends unknown[]> = T extends [infer F, ...infer R] ? [...Reverse<R>, F] : T;
type_ FlipArguments<T extends (...args: any) => unknown> = T extends ( ...args: infer Args ) => infer Result ? (...args: Reverse<Args>) => Result : T;
Solution by DoubleWoodLin #28701
// your answers
type Reverse<T extends unknown[]> = T extends [infer F, ...infer R] ? [...Reverse<R>, F] : T;
type FlipArguments<T extends (...args: any[]) => any> = T extends (...args: infer P) => infer U
? (...args: Reverse<P>) => U
: never;
Solution by daiki-skm #28235
type Push<T, U> = T extends any[] ? [...T, U] : never;
type FlipArguments<T extends (...args:any) => any, U extends any[] = []> =
T extends (...args: infer F) => infer R ?
F extends [...infer O, infer L] ?
FlipArguments<(...args: O) => R, Push<U, L>> : (...args: U) => R : never;
Solution by 8471919 #27732
type Reverse<T extends any[], P extends any[] = []> = T extends [infer L, ...infer R] ? Reverse<R, [L, ...P]>: P
type FlipArguments<T extends (...args: any[]) => any> = T extends (...args: infer A) => infer R ? (...args: Reverse<A>) => R: never
Solution by isntkyu #27713
type Reverse<T extends unknown[]> = T extends [infer First, ...infer Tail] ? [...Reverse<Tail>, First] : []
type FlipArguments<T extends (...args: any[]) => any > =
T extends (...args: infer P) => infer R ? (...args: Reverse<P>) => R : never
Solution by jjswifty #27636
type Reverse<T> = T extends [...infer Pre, infer Next] ? [Next, ...Reverse<Pre>] : []
type FlipArguments<T> = T extends (...args: infer Args) => infer Return ? (...args: Reverse<Args>) => Return : T
Solution by jiechliu #27451
type ReverseArg<T,R extends any[] = []> = T extends [...infer A, infer B] ? ReverseArg<A, [...R, B]>:R
type FlipArguments<T extends Function> = T extends (...args: infer A) => infer B ? (...args:ReverseArg<A>) => B : never
Solution by ZhipengYang0605 #27310
type Reverse<T extends unknown[]> = T extends [...infer Rest, infer Last]
? [Last, ...Reverse<Rest>]
: T
type FlipArguments<T extends (...args: never[]) => unknown> =
T extends (...args: infer P) => infer R
? (...args: Reverse<P>) => R
: never
Solution by HubooDeclan #27031
type Reverse<T extends unknown[]> = T extends [...infer R, infer L] ? R extends [] ? T : [L, ...Reverse<R>] : [];
type FlipArguments<T> = T extends (...args: infer P) => infer R ? (...args: Reverse<P>) => R : never;
Solution by smileboyi #26965
type Reverse<T extends unknown[]> = T extends [...infer V, infer R]
? [R, ...Reverse<V>]
: T;
type FlipArguments<T extends (...args: any) => any> = T extends (
...args: infer V
) => infer R
? (...args: Reverse<V>) => R
: never;
Solution by ryuji-1to #26884
type Reverse<T extends unknown[]> = T extends [infer First, ...infer Rest] ? [...Reverse<Rest>, First] : T;
type FlipArguments<T> = T extends (...args: infer Args) => infer ReturnType
? (...args: Reverse<Args>) => ReturnType
: never;
Solution by rldnd #26857
// your answers
type Reverse<T extends unknown[]> = T extends [...infer R, infer L] ? [L, ...Reverse<R>] : T;
type FlipArguments<T> = T extends (...arg: infer Arg) => infer R ? (...arg: Reverse<Arg>) => R : T
Solution by CheolMinBae #26679
type Reverse<T extends unknown[]> = T extends [infer First, ...infer Other] ? [...Reverse<Other>, First] : [];
type FlipArguments<T extends (...arg: any) => any> = T extends (...arg: infer First) => infer Other ? (...arg: Reverse<First>) => Other : never;
Solution by jsujeong #26676
type ReverseArgTpyes<Types extends any[]> = Types extends [...infer F, infer R] ? [R, ...ReverseArgTpyes<F>] : Types
type FlipArguments<T extends (...args: any[]) => any> = T extends (...args: infer Types) => infer U
? (...args: ReverseArgTpyes<Types>) => U
: never
Solution by HaoxueAllen #26535
type FlipArguments<T extends (...args: never[]) => unknown> = (...args: [...Flip<Parameters<T>>]) => ReturnType<T>
type Flip<T extends unknown[]> = T extends [] ? [] : T extends [infer Arg, ...infer Args] ? [...Flip<Args>, Arg] : never
Solution by ScarboroughCoral #26313