Type Challenges: 02852-medium-omitbytype Solution

type OmitByType<T, U extends PropertyKey | boolean> = {
  [k in keyof T as T[k] extends U ? never : k]: T[k]
}

Solution by wendao-liu #35054

type OmitByType<T, U> = {
  [Key in keyof T as T[Key] extends U ? never : Key] :  T[Key]
}

Solution by devshinthant #34933

// your answers
type OmitByType<T, U> = {
  [key in keyof T as T[key] extends U ? never : key]: T[key]
}

Solution by AndreGeng #34763

// your answers
type OmitByType<T, U> = {
  [k in keyof T as T[k] extends U ? never : k]: T[k]
}

Solution by Jayce-liang #34648

// your answers

type OmitByType<T, U> = {
  [K in keyof T as T[K] extends U ? never : K]: T[K]
}

Solution by gobielJonathan #34487

type OmitByType<T extends object, U> = {
  [K in keyof T as T[K] extends U ? never : K]: T[K]
}

Solution by ouzexi #34052

// your answers
```type OmitByType<T, U> = {
  [i in keyof T as T[i] extends U ? never : i]: T[i]
}

Solution by zhangshuaiqiang11 #33883

type OmitByType<T, U> = {
  [key in keyof T as T[key] extends U ? never : key]: T[key];
}

Solution by ZhipengYang0605 #33221

// your answers
type OmitByType<T, U> = { [P in keyof T as T[P] extends U ? never : P]: T[P] }

Solution by pea-sys #32928

// your answers
type OmitByType<T, U> = {
  [P in keyof T as T[P] extends U ? never : P]: T[P]
}

Solution by geweidong #32766

type OmitByType<T extends object, U> = { [K in keyof T as T[K] extends U ? never : K]: T[K] }

Solution by dev-hobin #32501

type OmitByType<T, U> = {
  [K in keyof T as Exclude<K, T[K] extends U ? K : never>]: T[K]
}

Solution by keyurparalkar #32317


type OmitByType<T, U> = {
  [Key in keyof T as T[Key] extends U ? never : Key]: T[Key]
}

Solution by maximallain #32216

type OmitByType<T, U> = {
  [K in keyof T as T[K] extends U ? never : K]: T[K]
}

Solution by ricky-fn #31877

type OmitByType<T, U> = {
  [P in keyof T as T[P] extends U ? never : P]: T[P]
}

Solution by vipulpathak113 #31754

// your answers
type OmitByType<T, U> = {[K in keyof T as T[K] extends U?never:K]:T[K] }

Solution by kangaroona #31020

type OmitByType<T, U> = {
  [K in keyof T as T[K] extends U ? never : K]: T[K] 
}```

Solution by kai-phan #30976

type OmitByType<T extends Record<string, any>, U> = {
  [K in keyof T as T[K] extends U ? never : K]: T[K]
}

// Deep version
type DeepOmitByType<T extends Record<string, any>, U> = {
  [K in keyof T as T[K] extends U ? never : K]: T[K] extends object ? DeepOmitByType<T[K], U> : T[K]
}

Solution by jjswifty #30904

type OmitByType<T extends object, E> = {
    [k in keyof T as T[k] extends E ? never : k]: T[k]
}

type OmitBoolean = OmitByType<{ name: string; count: number; enable: boolean }, boolean>;

Solution by sundial-dreams #29487

// your answers

type OmitByType<T, U> = {
  [K in keyof T as T[K] extends U ? never : K]: T[K]
}

Solution by kerolossamir165 #29395

type OmitByType<T, U> = {
  [K in keyof T as T[K] extends U ? never : K]: T[K];
};

Solution by DoubleWoodLin #28696

// your answers
type OmitByType<T, U> = {
  [P in keyof T as T[P] extends U ? never : P]: T[P]
}

Solution by daiki-skm #27747

type OmitByType<T extends Record<PropertyKey, any>, U> = {
  [K in keyof T as T[K] extends U ? never : K]: T[K]
}

Solution by jjswifty #27629

type OmitByType<T, U> = {
  [P in keyof T as T[P] extends U ? never : P]: T[P]
}

Solution by 8471919 #27522

type OmitByType<T, U> = {
  [K in keyof T as T[K] extends U ? never : K ]: T[K]
}

Solution by ZhipengYang0605 #27248

type OmitByType<T, K> = {[Key extends keyof T as T[Key] extends K ? never : Key ]: T[Key]}

Solution by vuongManabie #27222

type OmitByType<T, U> = { [K in keyof T as T[K] extends U ? never : K]: T[K] }

Solution by HubooDeclan #27033

type OmitByType<T, U> = { [K in keyof T as T[K] extends U ? never : K]: T[K] }

Solution by smileboyi #26951

type OmitByType<T, U> = {
  [K in keyof T as T[K] extends U ? never : K]: T[K];
};

Solution by ryuji-1to #26882

type OmitByType<T, U> = {
  [P in keyof T as T[P] extends U ? never : P]: T[P]
}

Solution by isntkyu #26875