type Concat<T extends readonly unknown[], U extends readonly unknown[] > = [...T, ...U]

Solution by EvgeniyKoch #36391

type Concat<T, U> = [...T, ...U]

Solution by Divcutu #36369

// your answers
type Concat<T extends readonly any[], U extends readonly any[]> = 
[...T, ...U] extends infer Y ? Y : never; 

Solution by justBadProgrammer #36365

type Concat<T extends readonly unknown[], U extends readonly unknown[]> = [...T, ...U]

Solution by HelloWook #36343

type Concat<T extends readonly any[], U extends readonly any[]> = [...T, ...U]

Solution by 1Alex4949031 #36313

type Concat<T extends readonly unknown[], U extends readonly unknown[]> = [...T, ...U]

Solution by EvgeniyKoch #36300

type Concat<T extends unknown[], U extends unknown[]> = [...T,...U]

"unknown is safer than any"

Solution by asylbekduldiev #36282

type Concat<T extends Readonly<Array<unknown>>, U extends Readonly<Array<unknown>>> = [...T, ...U]

Solution by Maxim-Do #36228

type Concat<T extends readonly any[], U extends readonly any[]> = [...T, ...U]

Solution by tungulin #36156

type Concat<T extends readonly any[], U extends readonly any[]> = [...T, ...U]

Solution by AleksandrShcherbackov #36146

type Concat<T extends any[] | readonly any[], U extends any[] | readonly any[]> = [...T, ...U]

Solution by buglavecz #36090

type Concat<T extends readonly any[], U extends readonly any[]> = [...T, ...U]

Solution by karazyabko #36030

type Concat<T extends readonly unknown[], U extends readonly unknown[]> = [...T, ...U];

Solution by reonce #36012

type Concat<T extends readonly any[], U extends readonly any[]> = [...T,...U];

Solution by chen8840 #35950

type Concat<T extends readonly any[], U extends readonly any[]> = [...T, ...U];

Solution by codingaring #35940

type TupleOrArray = any[] | readonly any[];
type Concat<T extends TupleOrArray, U extends TupleOrArray> = [...T, ...U];

Solution by Positivchik #35855

// 你的答案
type Concat<T extends readonly unknown[], U extends readonly unknown[]> = [...T, ...U]

Solution by naruto-823 #35792

type Concat<C extends any[], T extends any[]> = [...C, ...T];

Solution by Sensuele #35777

type Concat<T extends readonly any[], U extends readonly any []> =
  [...T, ...U];

Solution by XenoPOMP #35742

// 你的答案
type Concat<T extends any[], U extends any[]> = [...T, ...U]

Solution by ndwgg #35546

type Concat<T extends Array<unknown> | ReadonlyArray<unknown>, U extends Array<unknown> | ReadonlyArray<unknown>> = [...T, ...U]

Solution by gangnamssal #35486

type Concat<T extends readonly (PropertyKey| boolean)[], U extends readonly (PropertyKey| boolean)[]> =  [...T, ...U]

Solution by RanungPark #35438

// your answers

type Result<T extends unknown[], K extends unknown[]> = [...T, ...K];

const slicedData: Result<[1], [2]> = [1, 2];

Solution by Sathiyapramod #35416

type Concat<T extends readonly unknown[], U extends readonly unknown[]> = [...T, ...U];

Solution by sesolaga #35393

type Concat<T extends readonly unknown[], U extends readonly unknown[]> = [...T, ...U]

Solution by gyeounjeong #35359

// 你的答案
type Concat<T extends readonly any[], U extends readonly any[]> = [...T, ...U]
// or
type Concat<T extends ReadonlyArray<any>, U extends ReadonlyArray<any>> = [...T, ...U]

Solution by HoseaGuo #35130

// 你的答案

type Concat<T extends readonly unknown[], U extends readonly unknown[]> = [...T, ...U]

Solution by hexingdagmail #35050

type Tuple = readonly unknown[]
type Concat<T extends Tuple, P extends Tuple> = [...T, ...P]

Solution by ClarityOfMind #34992

type Concat<T extends readonly any[], U extends readonly any[]> = [...T, ...U]

Solution by huabingjenny #34981

type Concat<T extends any[], U extends any[]> = [...T, ...U];

Solution by raeyoung-kim #34941