type Last<T extends any[]> = T extends [...infer _, infer L] ? L : never

Solution by ChemieAi #36565

type Last<T extends any[]> = T extends [infer F, ...infer R]
  ? R extends [any, ...any]
    ? Last<R>
    : F
  : never;

Solution by josepderiu #36541

type Last<T extends any[]> = T extends [...any,infer P] ? P : never

Solution by tac-tac-go #36471

type Last<T extends any[]> = T extends [...infer Rest, infer L] ? L : never;

Solution by HtmlSeniorDev #36458

type Last<T extends any[]> = T extends [...infer K, infer L] ? L : never

Solution by gakki-san #36440

type Last<T extends any[]> = [never, ...T][T["length"]];

Solution by gakki-san #36439

type Last<T extends any[]> = T extends [...any[], infer L] ? L : never;

Solution by asylbekduldiev #36405

type Last<T extends any[]> = T extends [...infer R, infer F] ? F : never; 

Solution by AleksandrShcherbackov #36163

// your answers
type Last<T extends any[]> = T extends [...infer rest, infer last] ? last : never

Solution by lishenli1994 #36158

// 递归
type Last<T extends any[]> =
  T extends [infer First, ...infer Rest]
    ? Rest["length"] extends 0
    ? First
    : Last<Rest>
    : never;

Solution by qtycc-cc #35929

type Last<T extends any[]> = T['length'] extends 0 ? never : T extends [...any,infer U] ? U : 0;

Solution by tac-tac-go #35866

type Last<T extends any[]> = T extends [...infer _,infer Last] ? Last : never

Solution by EvilEl #35840

// 你的答案
// 基于Typescript 4.0.5
type Last<T extends any[]> = T extends [infer F, ...infer R]
  ? R["length"] extends 0
    ? F
    : [F, ...T][T["length"]]
  : never

Solution by a42195472 #35593

type Last<T extends any[]> = T extends [...any, infer L] ? L : never;

Solution by gangnamssal #35555

type Last<T extends any[]> = T extends [...infer A,infer U] ? U : never

Solution by TaueFenCheng #35534

type Last<T extends unknown[]> = T extends [...arg: unknown[], v:infer V] ? V : never

Solution by RanungPark #35481

// your answers
type arrOne = ["a", "b", "c"];
type arrTwo = [3, 2, 1];

type Last<T extends unknown[]> = T extends [...infer Pending, infer L] ? L : never;

const tail1: Last<arrOne> = "c";
const tail2: Last<arrTwo> = 1;

Solution by Sathiyapramod #35452

type Last<T extends any[]> = T extends [...infer Rest, infer Last] ? Last : never

Solution by eunsukimme #35122

type Last<T extends any[]> = T extends [...infer Rest, infer LastElement] ? LastElement : never

Solution by 2njeong #35081

// your answers

Solution by 2njeong #35080

type Last<T extends any[]> = T extends [...any[], infer L] ? L : never;

Solution by raeyoung-kim #35000

type Last<T extends any[]> = T extends [...any[], infer L] ? L : never;

Solution by 56aiden90 #34955

type Last<T extends any[]> = T extends [infer A, ...infer Rest] ? Rest extends [infer B, ...infer Rest2] ? Last : A : never;

我这个方法可能不是最好的，但是如果是type Last<T extends any[]> = T extends [...any, infer L] ? L : T这样的，在实际运行代码层面又是不合理的，type Last<T extends any[]> = [any, ...T][T["length"]];又不好理解，所以我还是采用最原始的做法。

Solution by shx123qwe #34916

type Last<T extends unknown[]> = T extends [infer Last]
  ? Last
  : T extends [infer _, ...infer Rest]
    ? Last<Rest>
    : never;

Solution by SayaOvO #34823

// your answers
type Last<T extends any[]> = T extends [...any, infer L] ? L : never;

Solution by zeyuanHong0 #34796

type Last<T extends any[]> = T extends [...any[], infer M] ? M : never;

Solution by nathan2slime #34656

type Last<T extends unknown[]> = [never, ...T][T["length"]];

// or 

type Last<T extends unknown[]> = T extends [... infer Head, infer Tail] ? Tail : never

Solution by binhdv155127 #34633

type Last<T extends any[]> = T['length'] extends 0 ? never : [any, ...T][T['length']]
// your answers

Solution by Rustamaha #34599

type Last<T extends any[]> = T['length'] extends 1
  ? T[0]
  : T extends [infer I, ...infer R] ? Last<R> : never
// your answers

Solution by Rustamaha #34598

type Last<T extends any[]> = T extends [...infer rest, infer F] ? F : never

Solution by Hailey0930 #34569