type MyPick<T, K extends keyof T> = {
[Property in K] : T[Property]
}
Solution by Muntazir-sd #35190
by Anthony Fu (@antfu) #easy #union #built-in
Implement the built-in Pick<T, K>
generic without using it.
Constructs a type by picking the set of properties K
from T
For example:
interface Todo {
title: string
description: string
completed: boolean
}
type TodoPreview = MyPick<Todo, 'title' | 'completed'>
const todo: TodoPreview = {
title: 'Clean room',
completed: false,
}
View on GitHub: https://tsch.js.org/4 */
/* _____________ Your Code Here _____________ */
type MyPick<T, K extends keyof T> = { [P in K]: T[P]; };
/* _____________ Test Cases _____________ */ import type { Equal, Expect } from '@type-challenges/utils'
type cases = [ Expect<Equal<Expected1, MyPick<Todo, 'title'>>>, Expect<Equal<Expected2, MyPick<Todo, 'title' | 'completed'>>>, // @ts-expect-error MyPick<Todo, 'title' | 'completed' | 'invalid'>, ]
interface Todo { title: string description: string completed: boolean }
interface Expected1 { title: string }
interface Expected2 { title: string completed: boolean }
/* _____________ Further Steps _____________ / /
Share your solutions: https://tsch.js.org/4/answer View solutions: https://tsch.js.org/4/solutions More Challenges: https://tsch.js.org */
Solution by leetflow #35153
type MyPick<T, K extends keyof T> = { [P in K]: T[P] }
Solution by JAGORING #35144
type MyPick<T, K extends keyof T> = {
[P in keyof T as P extends K ? P : never]: T[P]
};
Solution by lwfxzz #35114
type MyPick<T, K extends keyof T> = {
[key in K]: T[key]
}
Solution by chenweiCwCw #35058
// 你的答案
Solution by chenweiCwCw #35057
type MyPick<T, K> ={ [Key in keyof T as Key extends K? Key:never ]:T[Key] }
// 你的答案
Solution by Xiaofan-song #34958
// 你的答案
type MyPick<T, K extends keyof T> = {
[P in K]: T[P]
}
Solution by zhaiweile #34952
type MyPick<T, K extends keyof T> = {
[key in keyof T as key extends K ? key : never]: T[key];
};
K
type (must be subset of the keyof T
)key in keyof T as
means mapped type all the iterates over all keys in T
.key extends K ? key : never
: is conditional typekey
is assinable K
, it keeps the key,never
(it meas removes the key from the resulting type): T[key]
: preserves the original type of each selected property from T
.Solution by miju-Park #34915
type MyPick<T, K extends keyof T> = {
[key in K]: T[key]
}
Solution by jsk3342 #34893
type MyPick<T, K> = {
[key in ((keyof T) & K)]: T[key]
}
Solution by 56aiden90 #34865
type MyPick<T, K extends keyof T> = {[P in K]: T[P];};
Solution by PrahladMehta #34843
// your answers
Solution by PrahladMehta #34842
type MyPick<T, K extends keyof T> = {
[P in K]: T[P];
};
Solution by HrOkiG2 #34828
// your answers
type MyPick<T, K extends keyof T> = { [key in K]: T[key] };
Solution by eunsukimme #34805
type MyPick<T, K extends keyof T> = {
[P in K]: T[P]
}
Solution by heryTz #34794
type MyPick<T, K extends keyof T> = {
[k in K] : T[k]
}
Solution by Kim-Ji-Seop #34790
T
에서 K
프로퍼티만 선택해 새로운 오브젝트 타입을 만드는 내장 제네릭 Pick<T, K>
을 이를 사용하지 않고 구현하세요.
interface Todo {
title: string
description: string
completed: boolean
}
type TodoPreview = MyPick<Todo, 'title' | 'completed'>
const todo: TodoPreview = {
title: 'Clean room',
completed: false,
}
타입스크립트의 유틸리티 타입 중 하나로, 유틸리티 타입은 이미 정의해 놓은 타입을 변환할 때 유용한 타입이다.
Pick 타입은 특정 타입에서 몇 개의 속성을 선택하여 타입을 정의할 수 있으며 Pick<Type, Keys>
형식으로 작성할 수 있다. 이때, keys 값에는 문자열 리터럴
혹은 유니온 형식의 문자열 리터럴
이 올 수 있다.
interface Todo {
title: string
description: string
completed: boolean
}
// Todo타입에서 'title', 'completed' 속성을 선택하여 타입 정의
type TodoPreview = Pick<Todo, 'title' | 'completed'>
const todo: TodoPreview = {
title: 'Clean room',
completed: false,
}
Pick 타입을 유틸리티 타입을 사용하지 않고 직접 구현하는게 문제이므로 가져온 타입을 T
, 해당 타입의 키를 확장하는 K
를 선언하여 제네릭에서의 extends
를 통해 타입의 조건부 제한을 설정하고 Mapped Type
을 사용하여 타입을 정의합니다.
맵드 타입(Mapped Type)이란? 기존에 정의되어 있는 타입을 새로운 타입으로 변환해 주는 문법을 의미합니다.
// 제네릭 extends 활용으로 타입 제한 설정
type MyPick<T, K extends keyof T> = {
// Mapped type in 연산자를 통해 K 집합 타입의 요소들을 하나씩 치환
[P in K]: T[P];
}
Solution by MyeonghoonNam #34783
type MyPick<T, K extends keyof T> = { [P in K]: T[P] };
Solution by pomeranian91 #34767
type MyPick<T, K extends keyof T> = {
[key in K]: T[K]
}
Solution by kang-kibong #34740
// your answers
Solution by AdrienPiombini #34733
type MyPick<T, K extends keyof T> = {[key in K]: T[key]}
Solution by ainochi-kor #34723
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`// 你的答案
type MyPick<T, K extends keyof T> = { [key in K]: T[key]; }
/* _____________ 测试用例 _____________ */ import type { Equal, Expect } from '@type-challenges/utils'
type cases = [ Expect<Equal<Expected1, MyPick<Todo, 'title'>>>, Expect<Equal<Expected2, MyPick<Todo, 'title' | 'completed'>>>, // @ts-expect-error MyPick<Todo, 'title' | 'completed' | 'invalid'>, ]
interface Todo { title: string description: string completed: boolean }
interface Expected1 { title: string }
interface Expected2 { title: string completed: boolean }``
Solution by 1710929851 #34713
type MyPick<T, K extends keyof T> = {
[PropertyOfT in K]: T[PropertyOfT];
};
Solution by lephuthuc2001 #34694
type MyPick<T, K extends keyof T> = {
[k in K]: T[k]
}
Solution by Hailey0930 #34686
type MyPick<T, K extends keyof T> = {
[key in K]: T[key]
}
Solution by shuvro111 #34684
type MyPick<T, K extends keyof T> = {
[P in K]: T[P]
}
Solution by raeyoung-kim #34679
type MyPick<T, K extends keyof T> = {
[key in K]: T[key]
}
处理这个问题,令我加深了对泛型、继承、keyof、in的理解👍
Solution by oOzhuoxiaOo #34669
type MyPick<T, K> = K extends keyof T ? T[K] : never;
Solution by nathan2slime #34652